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5w^2-40w-100=0
a = 5; b = -40; c = -100;
Δ = b2-4ac
Δ = -402-4·5·(-100)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-60}{2*5}=\frac{-20}{10} =-2 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+60}{2*5}=\frac{100}{10} =10 $
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